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  • 06-11-2016
  • Chemistry
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Percentage compostion of carbon in CaCO3

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Moly42
Moly42 Moly42
  • 06-11-2016
Ca = 40.08 amu
C = 12.01 amu
O = 16 * 3 = 48 amu

40.08 + 12.01 + 48 = 100.09 total amu

12.01 / 100.09 = 0.1199 * 100 = about 12% C


To find percent composition carbon you do

12.01 amu divided by the total amu of compound times 100..

amu is just the atomic mass number of the element/compound

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