4804085321 4804085321
  • 10-02-2021
  • Mathematics
contestada

[tex]2x^2-20x=x^{2} -19[/tex]

Respuesta :

jimrgrant1 jimrgrant1
  • 10-02-2021

Answer:

x = 1, x = 19

Step-by-step explanation:

Given

2x² - 20x = x² - 19 ( subtract x² - 19 from both sides )

x² - 20x + 19 = 0 ← in standard form

(x - 1)(x - 19) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 19 = 0 ⇒ x = 19

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chloedeloycie
chloedeloycie chloedeloycie
  • 10-02-2021
x1 = 1 x2 = 19 if I’m correct
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