Answer:
6.14
Step-by-step explanation:
Given the function f(x)=x^(2)-5x-7, when f(x) = 0
x^(2)-5x-7 = 0
Using the general formula
x = 5±√5²-4(-7)/21(1)
x= 5±√25+28/2
x = 5±√53/2
x = -5±7.28/2
x = 5+7.28/2 and 5-7.28/2
x = 12.28/2 and -2.28/2
x = 6.14 and -1.14
Hence the positive zero is 6.14
