elhernaneez elhernaneez
  • 06-02-2021
  • Physics
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I =p/4pir^2 solving for r

Respuesta :

trihext
trihext trihext
  • 06-02-2021

Answer: [tex]r = \sqrt{\frac{p}{4pil}}[/tex]

Explanation:

[tex]l = \frac{p}{4pir^2} \\4pir^2l=p\\r^2 = \frac{p}{4pil} \\r = \sqrt{\frac{p}{4pil}}[/tex]

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