sgsimokaitis sgsimokaitis
  • 08-12-2020
  • Chemistry
contestada

how many grams are there in 0.270 mol of lead (II) nitrate?

Respuesta :

onfirekitten onfirekitten
  • 08-12-2020

Answer:

67.0 g Lead (ll) Nitrate

Explanation:

first, find you mass for each element

Pb= 207 g

N=14 g

207(2)+14=428 g

now convert to grams using the standard moles conversion

0.270 moles (248 g/1 mole) = 66.96

round to the correct number of significant figures, 3.

66.96= 67.0 g

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