Answer:
c = 0.043 j/ g. °C
Explanation:
Given data:
Amount of sample = 500 g
Initial temperature = 55.0°C
Final temperature = 25.0°C
Heat required released = 640 J
Specific heat capacity of sample = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25°C - 55°C
ΔT = -30°C
by putting values,
-640 J = 500 g × c × -30 °C
c = 640 J / 500 g× 30 °C
c = 640 J /15000 g. °C
c = 0.043 j/ g. °C
