wolfgirlolivia wolfgirlolivia

06-12-2020
Mathematics

contestada

F(x)= 2x^2+4x+10
G(x)= 3x-11
H(x)= 3x^3+x^2-21

The value of H(F(G(2)))

Respuesta :

sandeshsitoula6 sandeshsitoula6

06-12-2020

Step-by-step explanation:

H(F(6-11))

H(F(-5))

H(F(50-20+10))

H(40))

3×(40^3)+40^2-21

=193579

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