If AB ≅ DE , BC = EF, and ∠ACB ≅ ∠DFE, then ΔABC ≅ ΔDEF.

WILL MARK BRAINLIEST
PLZ ASAP

Answer: The statement is true.

Explanation: AB is approximately equal to DE. BC is equal to EF and angle ACB is approximately equal to angle DEF, therefore triangle ABC is approximately equal to triangle DEF.

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Ace248 Ace248 · Answer 2 · 2020-11-08T19:22:03+01:00

Ace248 Ace248

08-11-2020

Answer:

Cannot be determined

Step-by-step explanation:

It can't be determined because AB=DE, BC=EF, and <ACB=<DFE not <DEF which makes the rule SSA which doesn't prove congruency.

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If AB ≅ DE , BC = EF, and ∠ACB ≅ ∠DFE, then ΔABC ≅ ΔDEF.WILL MARK BRAINLIESTPLZ ASAP

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If AB ≅ DE , BC = EF, and ∠ACB ≅ ∠DFE, then ΔABC ≅ ΔDEF.

WILL MARK BRAINLIEST
PLZ ASAP