tehya134
tehya134 tehya134
  • 09-10-2020
  • Mathematics
contestada

4 - x + [tex]6^{2}[/tex] [tex]\geq[/tex] 21

Respuesta :

altavistard
altavistard altavistard
  • 12-10-2020

Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

4 - x + 6^2 ≥  21

becomes 4 - x + 36 ≥  21

Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

x ≤ 19

Please, include the instructions when you post a question.  Thanks.

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