[tex]f(x) = 2x + 3[/tex]
[tex]y = 2x + 3[/tex]
Subtract the sides of the equation minus 3
[tex]y - 3 = 2x[/tex]
Divided the sides of the equation by 2
[tex] \frac{y - 3}{2} = x \\ [/tex]
So ;
[tex] {f}^{ - 1}(x) = \frac{x - 3}{2} \\ [/tex]
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And we're done.
Thanks for watching buddy good luck.
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