Answer:
[tex]\Large \boxed{\sf \bf 2x^2-12x+10}[/tex]
Step-by-step explanation:
Hello,
As 1 and 5 are roots we can write, with a real number, the quadratic equation as
a(x-1)(x-5)
and as the leading coefficient is 2 then a = 2
It comes
[tex]2(x-1)(x-5)=2(x^2-6x+5)=2x^2-12x+10[/tex]
Thanks
