hahsafjbsbgg7163 hahsafjbsbgg7163
  • 09-09-2020
  • Physics
contestada

Find an expression for the square of the orbital period.

Respuesta :

hopemichael95
hopemichael95 hopemichael95
  • 09-09-2020

Answer:

T²= 4π²R³/GM

Explanation:

First we know that

Fg= Fc

Because centripetal force must equal gravitational force

So

GMm/R² = Mv²/R

But velocity is 2πR/T

So by substitution we have

GMm/R²= M (2πR/T)/T

We have

T²= 4π²R³/GM as period

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