Respuesta :

Alfpfeu

Answer:

Step-by-step explanation:

HEllo,

[tex](\sqrt{3})^n=3^{\frac{n}{2}}=\dfrac{3^x}{27^y}=3^x\times(3^3)^{-y}=3^{x-3y}\\\\<=>\dfrac{n}{2}=x-3y\\\\<=>\boxed{\sf \bf n= 2x-6y}[/tex]

Hope this helps

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