sophiesky
sophiesky
09-09-2016
Mathematics
contestada
[tex] \frac{x}{x-3}- \frac{2x-1}{1} [/tex]
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apologiabiology
apologiabiology
09-09-2016
get denoms the same
multiply the second equation by (x-3)/(x-3)
[tex] \frac{x}{x-3} - \frac{(2x-1)(x-3)}{(x-3)} = \frac{x-(2x-1)(x-3)}{(x-3)}= \frac{x-(2x^2-7x+3)}{(x-3)}= \frac{x-2x^2+7x-3}{(x-3)}[/tex][tex]= \frac{-2x^2+8x-3}{(x-3)}[/tex]
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