10-08-2020
Mathematics

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tomson1975 tomson1975

10-08-2020

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According to the properties of the radiation:

X^(a/b) = [tex]\sqrt[b]{X^a}[/tex]

So

X^(2/3) = [tex]\sqrt[3]{X^2}[/tex]

And

Y^(-3/4) = 1/Y^(3/4)

so 1/Y^(-3/4) = Y^(3/4) = [tex]\sqrt[4]{Y^3}[/tex]

Then we get

[tex]\sqrt[2]{X^3} .\sqrt[4]{Y^3}[/tex]

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