Answer:
[tex] (x+4)^2=4[/tex]
Step-by-step explanation:
[tex]x^2+8x+12=0\\
\implies (x^2+8x+16)+12=16\\
\implies (x+4)^2=16-12\\
\implies \boxed{(x+4)^2=4}[/tex]
(x +4)^2 = 4
if we add 4 to the expression x^2 + 8x + 12 we will have a perfect square which is shown as (x +4)^2
so (x +4)^2 = 4 is equivalent to the expression x^2 + 8x + 12
