sloandudley9463 sloandudley9463
  • 08-08-2020
  • Physics
contestada

an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the device

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cristoshiwa cristoshiwa
  • 09-08-2020

Answer: R=24.2Ω

Explanation: Power is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

P=V.i

P=R.i²

[tex]P=\frac{V^{2}}{R}[/tex]

The resistance of the system is:

[tex]P=\frac{V^{2}}{R}[/tex]

[tex]R=\frac{V^{2}}{P}[/tex]

[tex]R=\frac{110^{2}}{500}[/tex]

R = 24.2Ω

For the device, resistance is 24.2Ω.

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