greenleaves5 greenleaves5

09-07-2020
Physics

contestada

us
A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)

Respuesta :

ohiekulous ohiekulous

11-07-2020

Answer:

0.242

Explanation:

m = 13.3 kg

a =d= 2.42 m/s²

g = 10 m/s²

from the laws of friction F = ¶R

===> ¶ = F/R = ma/mg = a/g

¶ = a/g = 2.42/10 = 0.242

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