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09-06-2020
Chemistry

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What is the pOH of a base with a OH- concentration of 0.0500 x 10-11 M? PLEASEEEEEE ASAP

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gracee003 gracee003

09-06-2020

Answer:

poH= -log(oh^-)

= - log (0.500* 10^-11)

= =- log 0.5 + log (10^-11)

= -( -0.30 +(-11))

=+ 11.3

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