finn21 finn21
  • 06-06-2020
  • Mathematics
contestada

Help appreciated please and thank you​

Help appreciated please and thank you class=

Respuesta :

Hrishii
Hrishii Hrishii
  • 06-06-2020

Answer:

D. [tex] \frac{4 \sqrt{33} }{33} [/tex]

Step-by-step explanation:

[tex] \tan \alpha = \frac{4}{ \sqrt{33} } \\ = \frac{4}{ \sqrt{33} } \times \frac{ \sqrt{33} }{ \sqrt{33} } \\ \\ = \frac{4 \sqrt{33} }{ {( \sqrt{33)} }^{2} } \\ \\ \tan \alpha = \frac{4 \sqrt{33} }{33} [/tex]

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Аноним Аноним
  • 06-06-2020
The answer I think is d
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