Answer: log( 3 /x[2+y])
Step-by-step explanation:
Hi to answer this question we have to follow the next steps:
log 3x – 2 logx- log(2+y)]
Simplify the second term
log 3x – logx²- log(2+y)]
Use the quotient property of logarithms in the first 2 terms
log (3x / x²)- log(2+y)
log (3 / x)- log(2+y)
Use the quotient property of logarithms again
log (3/x ÷ [2+y])
Combine
log ( 3 / x [2+y])
