kalebanaya1 kalebanaya1
  • 06-05-2020
  • Mathematics
contestada

An isosceles triangle has side that are 20,20 and 16. how long is the altitude of the triangle?

Respuesta :

averixmpoy
averixmpoy averixmpoy
  • 06-05-2020

Answer:

[tex]4\sqrt{21}[/tex]

Step-by-step explanation:

16 is split into half to get 8. then use the pythagorean theorem to solve for the altitude.

a^2 + b^2 = c^2

8^2 + b^2 = 20^2

64 + b^2 = 400

b^2 = 336

b = [tex]\sqrt{336}[/tex]

simplify to [tex]4\sqrt{21}[/tex]

Answer Link
Chelboy
Chelboy Chelboy
  • 06-05-2020

Answer:18.3

Step-by-step explanation:

16/2=8

altitude=√(20^2-8^2)

altitude=√(20x20-8x8)

altitude=√(400-64)

altitude=√(336)

altitude=18.3

Answer Link

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