A water fountain jet shoots short spurts of water over a walkway. The water spurts reach a maximum height, then come down into a pond of water on the other side of the walkway. The height above the jet, h, of a spurt of water t seconds after leaving the jet can be found by the function h(t)equalsminus16tsquaredplus16t. Find the time it takes for the spurt of water to return to the jet's height; that is, when h(t)equals0.

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Muscardinus Muscardinus · Answer 1 · 2020-04-16T05:21:10+02:00

Answer:

The spurt of water takes 1 second to return to the jet's height.

Explanation:

The height above the jet, h, of a spurt of water t seconds after leaving the jet can be given by the function as follows :

[tex]h(t)=-16t^2+16t[/tex] .......(1)

We need to find the time it takes for the spurt of water to return to the jet's height i.e. when h(t) = 0

Equation (1) becomes :

[tex]h(t)=0\\\\-16t^2+16t=0\\\\16t(-t+1)=0\\\\t=0,t=1[/tex]

So, the spurt of water takes 1 second to return to the jet's height.