Answer:
[tex]A=440.7\ in^2[/tex]
Step-by-step explanation:
we know that
The area of a regular hexagon, is equal to the area of six congruent equilateral triangles
so
[tex]A=6[\frac{1}{2}(b)(h)][/tex]
we have
[tex]b=13\ in\\h=11.3\ in[/tex]
substitute
[tex]A=6[\frac{1}{2}(13)(11.3)]=440.7\ in^2[/tex]
