savi1028
savi1028 savi1028
  • 08-04-2020
  • Mathematics
contestada

f^(-2) =
fl-4) =
ff"(-2)) =

Respuesta :

Аноним Аноним
  • 08-04-2020

Answer:The line goes through the points (4,-3) and (0,-2), so its gradient is (-2-(-3))/(0-4) = -1/4. The y-intercept is -2 because f(0)=-2. So the equation of the line is y = -1/4 x - 2.This can be represented by the linear function f(x) = (-1/4)x - 2. The composite function ff is given by ff(x) = f(-1/4 x - 2) = (-1/4)((-1/4)x - 2) - 2 = x/16 - 3/2.HOPE'S THIS HELP'S

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