Respuesta :

Tsarina
1 mole of any gas at STP occupies 22.4 L.

Now,

The number of moles = (3×10^23 / 6.022×10^25)

which is approximately 2 × 10^(-2)

So the Volume is approximately = 0.02 × 22.4l = 0.448 l

Otras preguntas