arlenypenaa200 arlenypenaa200
  • 07-04-2020
  • Mathematics
contestada

In ΔNOP, the measure of ∠P=90°, the measure of ∠O=17°, and OP = 8.6 feet. Find the length of PN to the nearest tenth of a foot.

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thamimspartan thamimspartan
  • 12-04-2020

The length of PN is 2.63 feet

Explanation:

Given:

∠P=90°,

∠O=17°,

OP = 8.6 feet

PN = ?

The given triangle is a right angle triangle as one angle is 90°

We know:

[tex]tan \alpha = \frac{perpendicular}{base}[/tex]

[tex]tan(17^o) = \frac{PN}{OP} \\\\0.3057 = \frac{PN}{8.6} \\\\PN = 0.3057 X 8.6 feet\\\\PN = 2.63 feet[/tex]

Therefore, the length of PN is 2.63 feet

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