man20 man20
  • 10-07-2016
  • Mathematics
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Can someone please answer. There is one problem. There's a picture. Thank you!

Can someone please answer There is one problem Theres a picture Thank you class=

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konrad509
konrad509 konrad509
  • 10-07-2016
[tex]\displaystyle \binom{40}{12}=\dfrac{40!}{12!28!}=\dfrac{29\cdot30\cdot\ldots\cdot39\cdot40}{1\cdot2\cdot\ldots\cdot11\cdot12}=5,586,853,480[/tex]
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