Respuesta :

apologiabiology
remember pemdas
simpliify pathentsees, exponents then multiply divide add subtract

some exponential laws
[tex](xyz)^m=[(x)^m][(y)^m][(z)^m][/tex]
[tex](x^m)^n=x^{mn}[/tex]
[tex](x^m)(x^n)=x^{m+n}[/tex]

we have
(-5m^2q)^2(-3m^3q)

do each seperately
(-5m^2q)^2=
[(-5)^2][(m^2)^2][(q)^2]=
[25][m^4][q^2]=
25m^4q^2

second part

(-3m^3q)^3=
[(-3)^3][(m^3)^3][(q)^3]=
[-27][m^9][q^3]=
-27m^9q^3

so we multiply them together

(25m^4q^2)(-27m^9q^3)=
(25)(m^4)(q^2)(-27)(m^9)(q^3)=
(25)(-27)(m^4)(m^9)(q^2)(q^3)=
(-675)(m^13)(q^5)=
-675m^13q^5


answer is first one

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