jejdhdh jejdhdh
  • 06-03-2020
  • Mathematics
contestada

Let 0 be an angle such that cot 0 = -4/7 and sec 0 >0.
Find the exact values of cos 0 and csc 0.

Respuesta :

amna04352
amna04352 amna04352
  • 06-03-2020

Answer:

Cos 0 = 4/sqrt(65)

Cosec 0 = -sqrt(65)/7

Step-by-step explanation:

Cot 0 = -4/7

Tan 0 = -7/4

1 +Tan²0 = sec²0

1 + 49/16 = 65/16 = sec²0

Sec 0 = sqrt(65)/4

Cos 0 = 1 ÷ sec 0

Cos 0 = 4/sqrt(65) or 4sqrt(65)/65

Cosec 0 = cot 0 × sec 0

= -4/7 × sqrt(65)/4

= -sqrt(65)/7

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