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A chemist prepares a solution of magnesium fluoride (MgF_2), by measuring out 0.031 g of magnesium fluoride into a 250. mL. Volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist magnesium fluoride solution. Round your answer to 2 significant digits. _____ mol/l.

Respuesta :

Answer:

The concentration of the magnesium fluoride solution is 0.0020 M

Explanation:

Step 1: Data given

Mass of MgF2 = 0.031 grams

volume = 250 mL = 0.250 L

Molar mass of MgF2 = 62.3 g/mol

Step 2: Calculate moles

Moles MgF2 = mass MgF2 / molar mass MgF2

Moles MgF2 = 0.031 grams / 62.3 g/mol

Moles MgF2 = 4.98 *10^-4 moles

Step 3: Calculate concentration of MgF2

Concentration MgF2 = moles MgF2 / volume

Concentration MgF2 = 4.98 *10^-4 / 0.250 L

Concentration = 0.0020 M

The concentration of the magnesium fluoride solution is 0.0020 M

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