Seudónimo Seudónimo
  • 16-01-2020
  • Mathematics
contestada

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​

SOMEONE PLEASE HELP ME ASAP PLEASE class=

Respuesta :

inchu420 inchu420
  • 28-01-2020

Answer:

Therefore,

[tex]a_{21}=2[/tex]

Step-by-step explanation:

Given:

[tex]A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right][/tex]

To Find:

a₂₁ = ?

Solution:

Let,

[tex]A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right][/tex]

We require  ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ [tex]a_{21}=2[/tex]

Therefore,

[tex]a_{21}=2[/tex]

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