maryanne50
maryanne50 maryanne50
  • 14-12-2019
  • Mathematics
contestada

solve for x and y ,32base x+51base y and 23base x +42 base y =710. ,number bases interms of simultaneous equation​

Respuesta :

andrew8253 andrew8253
  • 21-12-2019

Answer:

[tex]x = -348.5, y = 350.5[/tex]

Step-by-step explanation:

32base x means [tex]3x + 2[/tex]

Similarly, 32base x+51base y equals to [tex]3x + 2 + 5y + 1 = 3x + 5y + 3[/tex]

and 23base x +42 base y means [tex]2x + 3 + 4y + 2 = 2x + 4y + 5[/tex]

As per the given condition, [tex]3x + 5y + 3 = 2x + 4y + 5\\x + y = 2[/tex]

Putting, [tex]y = 2 - x[/tex] in [tex]2x + 4y + 5 = 710[/tex], we get

[tex]2x + 4y = 705\\2x + 4(2 - x) = 705\\8 - 2x = 705\\4 - x = 352.5\\x = -348.5[/tex]

[tex]y = 2 - x = 2 - (-348.5) = 2 + 348.5 = 350.5[/tex]

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