Answer:
Option D). 171 feet is correct
Step-by-step explanation:
Given that a toy rocket is launched from 42 feet above the ground.
The height is rocket is given by f(t)=[tex]-16t^{2} +91t+42[/tex]
To find the height of the rocket above the ground after 3seconds :
Given that f(0)=42
Take t=3
f(t)=[tex]-16t^{2} +91t+42[/tex]
f(3)=[tex]-16(3)^{2} +91(3)+42[/tex]
f(3)=[tex]-16(9) +91(3)+42[/tex]
f(3)=[tex]-144 +273+42[/tex]
f(3)=171 feet
Therefore, option D). 171 feet is correct
