De4kTamaman
De4kTamaman De4kTamaman
  • 11-06-2016
  • Mathematics
contestada

If the value of sinx=0.42, what is cos x?

Respuesta :

Tareki
Tareki Tareki
  • 13-06-2016
from the relation of 
sin(x)^2 + cos(x)^2 = 1 
(0.42)^2 + cos(x)^2 = 1 
cos(x)^2 = 1 - (0.42)^2 
cos(x) = √(1-(0.42)^2)
cos(x) = 0.9075
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