Respuesta :

hyperrspace

[tex]\frac{5x}{y^2}\\\\\frac{5(-2)}{-4^2} = \frac{-10}{16}=-\frac{5}{8}\\\\\frac{5(0)}{-4^2}=\frac{0}{16}=0\\\\\frac{5(-4)}{0^2}=\frac{-20}{0}=[/tex]∅

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