jfarrar02 jfarrar02
  • 06-06-2019
  • Mathematics
contestada

(x – 3)³
Given: (x – y)³ = x³ – 3x²y + 3xy² – y³

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 06-06-2019

ANSWER

[tex]{(x - 3)}^{3} = {x}^{3} - 9 {x}^{2} + 27x - 27[/tex]

EXPLANATION

We want to expand:

[tex] {(x - 3)}^3[/tex]

Using the identity;

[tex] {(x - y)}^{3} = {x}^{3} - 3 {x}^{2}y + 3x {y}^{2} - {y}^{3} [/tex]

We substitute y=3 into the above identity to obtain:

[tex] {(x - 3)}^{3} = {x}^{3} - 3 {x}^{2}(3) + 3x( {3}^{2} ) - {(3)}^{3} [/tex]

Let us simplify to get:

[tex]{(x - 3)}^{3} = {x}^{3} - 9 {x}^{2} + 27x - 27[/tex]

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