Answer:
[tex]4 \pi[/tex]
Explanation:
First of all, let's convert 2.0 rev into radians:
[tex]1.0 rev = 2\pi rad\\2.0 rev = 4 \pi rad[/tex]
This means that the angular speed of the wheel is
[tex]\omega = 2.0 rev/s = 4 \pi rad/s[/tex]
The angle through which the wheel rotates in a time t is given by
[tex]\theta=\omega t[/tex]
And substituting t=1.0 s, we find
[tex]\theta=(4\pi rad/s)(1.0 s)=4 \pi rad[/tex]
