Answer:
[tex]\large\boxed{p=54}[/tex]
Step-by-step explanation:
[tex]\dfrac{1}{3}p+7=25\qquad\text{subtract 7 from both sides}\\\\\dfrac{1}{3}p+7-7=25-7\\\\\dfrac{1}{3}p=18\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}}p=3\cdot18\\\\p=54[/tex]
