polkster221 polkster221
  • 10-04-2019
  • Mathematics
contestada

Need some math help!!!
Factor the polynomial by grouping: 12p^3 − 21 p^2 + 28p − 49

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BettaRasbora
BettaRasbora BettaRasbora
  • 10-04-2019

Answer:

[tex]\left(4p-7\right)\left(3p^2+7\right)[/tex]

Step-by-step explanation:

[tex]12p^3-21p^2+28p-49[/tex]

[tex]\left(12p^3-21p^2\right)+\left(28p-49\right)[/tex]

[tex]7\left(4p-7\right)[/tex]

[tex]3p^2\left(4p-7\right)[/tex]

[tex]7\left(4p-7\right)+3p^2\left(4p-7\right)[/tex]

[tex]\left(4p-7\right)\left(3p^2+7\right)[/tex]

Answer Link
Аноним Аноним
  • 10-04-2019
12p³ – 21p² + 28p – 49

3p²(4p–7) + 7(4p–7)

(4p–7)(3p+7)
Answer Link

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