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  • 07-03-2019
  • Mathematics
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find the perimeter of a square with an area of 702.25

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UserX UserX
  • 11-03-2019

area of a square= 702.25

A= side square

let's take side of a square= a

therefore,

702.25= a^2

a= āˆš702.25 = 26.5

perimeter (P) of a square= 4a

P = 4x 26.5= 106

so perimeter of a square is 106

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