mattiemattoos mattiemattoos
  • 07-02-2019
  • Mathematics
contestada

The equation of the hyperbola with center at (0, 0) opening horizontally, with a = 2, b = 5 is:

Respuesta :

rejkjavik rejkjavik
  • 07-02-2019

Answer:

[tex]\frac{x^2}{4}-\frac{y^2}{25} =1[/tex]

Step-by-step explanation:

we are given

center =(0,0)

we can compare with

center=(h,k)=(0,0)

so, h=0 and k=0

a=2 and b=5

now, we can use equation of hyperbola formula

[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1[/tex]

now, we can plug values

[tex]\frac{(x-0)^2}{2^2}-\frac{(y-0)^2}{5^2} =1[/tex]

we can simplify it

and we get equation of hyperbola as

[tex]\frac{x^2}{4}-\frac{y^2}{25} =1[/tex]


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