Answer:
option-A
Step-by-step explanation:
we are given
Dividend is
[tex]6x^2-19x+10[/tex]
Divisor is
[tex]2x-5[/tex]
we can use long division method
we get
Remainder is
=0
Quotient is
[tex]3x-2[/tex]
so, we can write as
[tex]\frac{6x^2-19x+10}{2x-5}=3x-2+\frac{0}{2x-5}[/tex]
[tex]\frac{6x^2-19x+10}{2x-5}=3x-2[/tex]
