littlemisshelper littlemisshelper

06-01-2019
Mathematics

contestada

Given sinθ=4/7 and θ lies in Quadrant II .

What is the exact value of cosθ in simplified form?

−4√33/33

−√33/4

√33/7

−√33/7

Respuesta :

06-01-2019

Answer:−√33/7

Step-by-step explanation:

Second quadrant implies cos negative, as cos is projection from

unit circle to x axis.

sin^2+cos^2=1

cos= sqrt(1-sin^2)

sin^2 = 16/49

1-sin^2 = 33/49

sin= -sqrt(33)/7

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