Answer:
112, 119 and 126.
Step-by-step explanation:
Let the consecutive multiples of 7 be 7n, 7(n+1) and 7(n+2) where n is an integer, then:-
7n + 7n + 7 + 7n + 14 = 357
21n + 21 = 357
21(n + 1) = 357
n = (357/21) - 1
n = 17 + 1 = 16.
So the numbers are 7*16 = 112, 7*17 = 119 and 7*18 = 126.
