Answer: B) [tex]\frac{2}{x}[/tex]
Step-by-step explanation:
[tex]\frac{x^{2}+8x}{3x^{2}+3x} - \frac{x^{2}+2x-6}{3x^{2}+3x}[/tex]
= [tex]\frac{x^{2}+8x- x^{2}-2x+6}{3x^{2}+3x} [/tex]
= [tex]\frac{6x+6}{3x^{2}+3x}[/tex]
= [tex]\frac{6(x+1)}{3x(x+1)}[/tex]
= [tex]\frac{6}{3x}[/tex]
= [tex]\frac{2}{x}[/tex]
