cgfloyd32 cgfloyd32
  • 06-12-2018
  • Mathematics
contestada

y^2/y-3 x y^2-y-6/y^2+1y

Respuesta :

Аноним Аноним
  • 06-12-2018

Answer:

x-2y=6

x=2y+6


x•2-4y•2=24

(2y+6)•2-4y•2=24

(2y+6)•2-8y=24

4y+12-8y=24

12-4y=24

-4y=12

y=-3


a=x+2y+(x+2y)•2+(x+2y)•3+(x+2y)•4


a=(2y+6)+2y+((2y+6)+2y)•2+((2y+6)+2y)•3+((2y+6)+2y)•4


a=(2(-3)+6)+2(-3)+((2(-3)+6)+2(-3))•2+((2(-3)+6)+2(-3))•3+((2(-3)+6)+2(-3))•4


a=(-6+6)-6+((-6+6)-6)•2+((-6+6)-6)•3+((-6+6)-6)•4


a=0-6-6•2-6•3-6•4


a=-6-12-18-24

a=-60



OR


x-2y=6

x=2y+6





Utilizați FOIL


















Step-by-step explanation:


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