isabellainksow87vn isabellainksow87vn
  • 08-11-2018
  • Mathematics
contestada

m∠GAH = 62° m∠ADB = 148° Find the m∠AFD.

mGAH 62 mADB 148 Find the mAFD class=

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 08-11-2018

if GAH = 62  then HAD = 118

because

GAH + HAD = 180  straight line

62+ HAD = 180

subtract 62 from each side

hAD = 118

FAD = 62

FAD + HAD = 180  it is a straight line

FAD +118 = 180

ADF + adb = 180 forms a straight line

ADF + 148 = 180

ADF = 32

A triangle = 180 degree

AFD + ADF + FAD = 180

AFD + 32+62 =180

AFD +94=180

AFD = 86



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