Answer: Option (B) is the correct answer.
Explanation:
Reaction between the given reactants will be as follows.
[tex]Fe(C_{2}H_{3}O_{2})_{2} + KI \rightarrow K(C_{2}H_{3}O_{2})_{2} + FeI_{2}[/tex]
Therefore, we can see that the above reaction results in the formation of potassium acetate and iron(II) iodide.
Out of which iron(II) iodide [tex](FeI_{2})[/tex] is the precipitate.