To distribute the 2/3, this is what you do.
2/3[8(5-2)^2 + 3*2] = (2/3)(8)(5-2)^2 + (2/3)(3*2) =
Now you can continue. You need to follow the correct order of operations.
= (2/3)(8)(3^2) + (2/3)(6)
= (2/3)(8)(9) + 4
= (2/3)(9)(8) + 4
= (6)(8) + 4
= 48 + 4
= 52
This is how I would have done it.
2/3[8(5-2)^2 + 3*2] =
= 2/3[8(3)^2 + 6]
= 2/3[8 * 9 + 6]
= 2/3[72 + 6]
= 2/3[78]
= 2 * 1/3(78)
= 2 * 26
= 52
